INSERT INTO departments(department_id, department_name, manager_id, location_id)VALUES (70, 'Public Relation', 100,1700);
INSERT INTO departments(department_id, department_name)VALUES (30, 'Purchasing');
INSERT INTO departmentsVALUES (100, 'Finance', NULL,NULL);
INSERT INTO employess (employee_id, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id)VALUES (133, 'Louis', ' Popp', 'LPOPP', '515.124.4567', SYSDATE, 'AC_ACCOUNT', 6900, NULL, 205, 100);
INSERT INTO employees
INSERT INTO department612(department_id, department_name, location_id)VALUES (&department_id, '&department_name', &location_id);
UPDATE employeesSET department_id = 70WHERE employee_id = 133;
UPDATE employeesSET job_id = (SELECT job_idFROM employeesWHERE employee_id = 205),salary = (SELECT salaryFROM employeesWHERE employee_id = 205)WHERE employee_id = 144;
DELETE FROM departmentsWHERE department_name = ‘Finance’;
LATIHAN
CREATE TABLE DEPARTMENT612AS SELECT * FROM DEPARMENTS
1. INSERT DATA BARU KE DALAM TABLE DEPARTMENT + NIM(TIGA DIGIT TERAKHIR)
DEPARTMENT_ID – DEPARTMENT_NAME – MANAGER_ID – LOCATION_ID
1135 MARKETING 100 110
1175 ACCOUNTING 80 90
188 ADMINISTRASI 90 70
2. TAMPILKAN DATA DEPARTMENTS YANG DEPARTMENT_IDNYA ADALAH 1135, 1175, 1188
CREATE TABLE department612AS SELECT * FROM DEPARTMENTS
INSERT INTO department612(department_id, department_name, manager_id, location_id)VALUES (&department_id, '&department_name', &manager_id, &location_id);
SELECT department_id AS "ID Departmen ", department_name AS "Nama Department", manager_id AS "ID Manager", location_id AS "ID Lokasi"FROM department612WHERE department_id = 1135OR department_id = 1175OR department_id = 1188;
3. UBAH DEPARTMENT-NAME MARKETING MENJADI FINANCE MANAGER ID = 120 DAN LOCATION ID = 80
UPDATE department612SET manager_id = 120, department_name = 'FINANCE', location_id = 80WHERE department_name = 'marketing'
4. HAPUS DEPARTMENT ACOUNTING
DELETE FROM department612WHERE department_name= 'Accounting'
SELECT employee_id, &last_name, salary, department_idFROM employeesWHERE manager_id = &last_name;



No comments:
Post a Comment